Saturday, 31 December 2011
Project Info Re-Posted
I have decided that giving you the Holiday Break to finish your projects may be better than having them due before the break. Presentations will be on Wednesday, January 4 and Thursday, January 5. If you would prefer to present before the break, speak to me and we will arrange that.
The presentations will be as follows:
Wednesday, January 4
Michelle
Aaron
Alex
Kelsey
Jeff
Nina
Brydon
Emily
Colby
Joel
Thursday, January 5
Sarah
Amy
Koralyn
Allysa
Tanner
Cody
Taryn
Miranda
You should email your presentation and other files to be displayed on the SmartBoard ahead of time. Email my mrbanow at gmail.com account. If you have any materials that are not digital, please bring them the day of your presentation and hand them in to me.
If you have questions now or over the break, email me and I will get back to you fairly quickly.
Good luck and have some fun! I hope your topic interests you!
Friday, 16 December 2011
Next Stages in the Project: Data and Controversy
- will you discuss mean, median, or mode?
- is your data Normally distributed?
- do you know that sample size and margin of error/confidence level for the data you found online?
- see pages 284-286 for more suggestions
- have you found two sources that provide contradictory information or data?
- does the contradictory data represent different viewpoints? (eg. is the data being provided by a group that would want a certain outcome?)
- see pages 352-353 for more ideas
Wednesday, 14 December 2011
6.6 Optimazation Problems: Linear Programming
The steps are as followed:
:)
6.4 and 6. 5 Optimization Problems
:)
In 6.3, we learned that what kind of numbers were dealing with contribute to our answer. This still applies to 6.4.
In 6.4, we learned about optimization problems. In an optimization problem, it asks you for the maximum and minimum possible solution.
Optimization problem
a problem where a quantity must be maximized or minimized following a set of guidlines or conditions.
Constraint
A limiting condition of the optimization problem being modelled, represented by a linear inequality.
Objective function
in an optimization problem, the equation that represents the relationship between the two variables in the system of linear inequalities and the quantity to be optimized.
Feasible region
The solution for a system of linear inequalities that is modelling an optimization problem.
The area in yellow represents the feasible region.
When graphins linear inequalities we must remember which part of the inequality goes on certain areas of the graph.
We then went over the last page of our 6.4 booklet.
We found out that you can tell you're dealing with an optimization problem if you have to find the minimum or maximum.
We found that the constraints are the linear inequalities in the problem.
We did practice on pages 330-331 # 2,3,5,6.
In 6.5 we looked at the race car and suv problem again.
We realised that the maximum and minimum was on the vertices of the feasible region, but we had to find out which two vertices.
The objective function to optiimize was: C = 8r + 12s
C = cost
r = race cars
s = suvs
We found that (60, 40) was the maximum.
C = 12(60) + 8(40)
C= $1040
We found that (30, 40) was the minimum.
C = 12(30) + 8(40)
C = $680
But does the minimum cost satisfy all the constraints?
Constraints:
r<40 (less than or equal to)
s<60 (less than or equal to)
s+r>70 (greater than or equal to)
YES IT SATISFIES ALL CONSTRAINTS!
We then did practice questions on pages 334-335 #1-3
here is a math video to brighten your day! lolol
http://www.youtube.com/watch?v=cgEuUzHYvOY">
Next will be Aaron :D
Friday, 9 December 2011
Extra Assistance for Graphing Linear Inequalities
Writing an Inequality for a Given Graph Video
Solving a System of Linear Inequalities Video - note: @ 3:50 he accidentally says 6/4 equals 6. The b-values and y-intercept should be 3/2 or 1.5, not 6. Also, in this video he has three inequalities. For 6.2 and 6.3 we only had two in a question.
Online Quiz - Choose Check Answer to verify if you have done it correctly
Wednesday, 7 December 2011
6.3 Graphing to Solve Systems of Linear Inequalities
Monday, 5 December 2011
6.0 Systems of Linear Inequations
Today in class we looked at graphing inequalities. An inequality says that two values are not equal.
Saturday, 3 December 2011
Review of Terms and Connections
Monday, 28 November 2011
5.6 p. 275 #7 Form
Complete the question by filling out this form:
https://docs.google.com/spreadsheet/viewform?hl=en_US&formkey=dDdkVkVvTXRCSlJfTnAzMDhUbGlhdUE6MQ#gid=0
This must be complete by Friday, December 2.
Thanks.
Sunday, 27 November 2011
Project
I have decided that giving you the Holiday Break to finish your projects may be better than having them due before the break. Presentations will be on Wednesday, January 4 and Thursday, January 5. If you would prefer to present before the break, speak to me and we will arrange that.
The presentations will be as follows:
Wednesday, January 4
Michelle
Aaron
Alex
Kelsey
Jeff
Nina
Brydon
Emily
Colby
Joel
Thursday, January 5
Sarah
Amy
Koralyn
Allysa
Tanner
Cody
Taryn
Miranda
You should email your presentation and other files to be displayed on the SmartBoard ahead of time. Email my mrbanow at gmail.com account. If you have any materials that are not digital, please bring them the day of your presentation and hand them in to me.
If you have questions now or over the break, email me and I will get back to you fairly quickly.
Good luck and have some fun! I hope your topic interests you!
Friday, 18 November 2011
Statistical Analysis Exam
On Monday, November 21 there is an Open Book exam on sections 5.1-5.4.
The key concepts are:
- mean
- standard deviation
- frequency distribution tables
- histograms
- frequency polygons
- Normal distribution
Standard Deviation Calculator
http://www.numberempire.com/statisticscalculator.php On this one, check off Mean and Standard Deviation
http://www.miniwebtool.com/standard-deviation-calculator/ Works like a charm!
Good luck with your assignment!
Thursday, 17 November 2011
5.4 NORMAL DISTRBUTION CURVE
The blue one is a bi- modal and the orange one is uniform
Than we did a thing that involved rolling a dice 50 times and recording the sum of the numbers
Than we combined the whole class’ results and made the histogram
It was like the purple one with the top ones being 7 and 8
Than we looked at this graph
Next is joel
Monday, 14 November 2011
Standard Deviation
"The coach of a girls' basketball team keeps stats on all of the players. Near the end of one game, the score is tied and the starting point guard gets fouled out. He needs to make a substitution. There are five girls on the bench who can sub in for the point guard."
The stats for the players were stated next.
Then we were asked which player was most consistent. We found that Paige was most consistent because her percentages were all between 33-35. They were not scattered, therefore they were consistent.
After that it said that the coach found that Paige and Patrice's values were close in value. He compared them more closely using standard deviation (a measure of the dispersion or scatter of data values in relation to the mean.)
We followed these steps to calculate the standard deviation for Paige:
-Determine the mean of Paige's shooting percentage.
(add all of Paige's percentages then divide by the amount of percentages there is. In this case there is ten.) We found that Paige's mean was 33.9.
-Calculate the deviation of each field goal percentage.
(Take one percentage and subtract it from the mean. Continue doing this with all the percentages.)
EX. 34-33.9=.1
-Calculate the squares of the deviations.
EX. The square root of .1 is .01. (Square root all deviations.)
-Fill in the values into the chart on the second page of the handout.
-Determine the standard deviation by:
-determining the mean of the squares of deviations.
(add all the squares of deviations and divide by 10)
Our answer was .69
-determining the square root of the mean from the step above^:
The square root of .69 is .8307.
Then we did the steps above for Patrice.
Next, we were asked who was more consistent between the two players. Our answer was Paige because .8307 is a smaller standard deviation than 1.4976(Patrice's standard deviation) and a smaller number means that here is more consistency.
We then calculated the mean and standard deviation using a graphing calculator. To do this, you must follow these steps:
-Stat
-Edit
-Enter the numbers
-Stat
-Calc
-1-var stats
-Enter.
(I probably forgot a step.)
We didn't finish the whole sheet but we will be finishing the rest in class tomorrow.
Next up is Colby.
Monday, 7 November 2011
5.1 Exploring Data
Today we were supposed to hand in our diagnostic tests which the majority of people didn't do, so remember to hand those in asap. We then worked on a sheet given to us on section 5.1 Exploring Data, and we had to find the mean, median, mode and range for the life of a car battery. We discussed the results and found that based on our data neither brand x nor brand y were a better choice, but it depended on whether or not the consumer was willing to take a risk on purchasing a battery that could either last longer or shorter than the average time. We learned one new term which was dispersion.
Dispersion is a measure that varies by the spread among the data in a set; dispersion has a value of zero if all the data in a set is identical, and it increases in value as the data becomes more spread out.
After that we were assigned Pg. 212 #2 and 3.
The next person to write the blog will be Brydon. :)
Sunday, 6 November 2011
Chapter 5: Statistical Reasoning
We looked at page 207 and discussed on how statistics help monitor the polar bear population, and how it can determine whether the population is stabilizing or taking a decline. We figured that by using inductive reasoning, one could predict the future outcome of the population.
Next, we looked at page 208 and 209 to apply our potentially new-found knowledge of mean, median, and mode values. The definitions for these terms are as follows:
Mean: A measure of central tendency determined by dividing the sum of all the values in a data set by the number of values in the set.
Median: A measure of central tendency represented by the middle value of an ordered data set.
Mode: A measure of central tendency represented by the value that occurs most often in a data set.
An example in which we can apply these terms is:
Let's say that this represents the size in cm of the diameter of school spheres. The mean is 47.857 cm (add the numbers up, 335, and divide by the amount of numbers, 7). The median is 50 cm (the middle column holds the 50 cm), and the mode is 20 (the only number repeated twice).
We also went over questions A-E on page 209. From doing so we learned about ranges (the difference between the maximum and the minimum value), outliers (a value in a data set that is very different from the others), utilized our knowledge about central tendencies to determine values for the 3 companies' salaries on page 208, and learned about line plots.
At the end of class, we were given our marks for our Oblique Triangle Trigonometry test, and were assigned the Chapter 5 diagnostic test, which was expected to be done by Monday.
The next person to make a blog will be Nina.
Friday, 4 November 2011
How to Rewrite Your Sine and Cosine Laws Exam
- understand and apply the Ambiguous Case
- solve written problems involving oblique triangles
- talk to Mr. Banow about coming in at a lunch hour to practice
- hand in all assignments from Chapters 3 and 4
- complete p. 200 #3, 5, 6, 7, 8 and p. 195 # 11 (I used to have 8 on this list - skip it) - You need to show all diagrams and calculations. You may work on this during the lunch hour you come to work
- schedule a second lunch hour to write the exam
Wednesday, 2 November 2011
4.4 Solving Problems Using Obtuse Triangles
Example. a surveyor in a helicopter wants to know the width of Garibaldi Lake. He starts 1610m above the forest and observes the angles of depression to both ends measuring 45 degrees and 82 degrees.
He the figured out the angles in the triangle to be 45 degrees 37 degrees and 98 degrees then used the right triangle it made with the trees and found the far distance to the lake and it was 2237.9m
using sine law he found the lake to be 1384m in width.
Tuesday, 1 November 2011
Monday, 31 October 2011
4.3 The Ambiguous Case of the Sine Law
On Friday, we started 4.3 and learnt Ambiguous cases. Ambiguous means unclear, unknown. An ambiguous case is a situation where two triangles can be drawn given the available information; the ambiguous case can occur when the given measurements are the lengths of two sides and the measure of an angle that is not contained by the two sides. (A.S.S. to remember).
We learnt that after you calculate 'h' using SOH CAH TOA you can determine how many triangles you can make. If 'h' is longer than the given side (5.5) you can only form 1 triangle. If 'h' is shorter than the length you calculated (3.5) you cannot form any triangles, and if the length of 'h' is in between what you calculated (3.5) and the given side (5.5) you can make 2 triangles.
To start solving an ambiguous case you have to:
1. Calculate the minimum length to make 1 triangle.
2. Compare minimum length to given length
This will show you the amount of triangles you will be able to make. Once you have completed this and two triangles can be made, you have to cr
eate two cases to show the two possibilities of what the triangle could look like using sine or cosine law, which we learnt in previous units.
The next person will be Brydon! :)
Thursday, 27 October 2011
4.1 exploring the primary trigonometric ratios of obtuse angles
sinx=sin(180-x)
cosx=cos(180-x)
tanx=tan(180-x)
There are relationships between the value of a primary trigonometri ratio for an acute angle and the value of the same primary trigonometric ratio for the supplement of the acute angle.
We used sin and cosine laws to determine the sine lengths and angle measures in acute oblique triangles.
the next person to write the blog is the person with the smallest hands
Wednesday, 26 October 2011
Bonus Problem!
Complete and submit this problem before Wednesday, Nov. 2 to receive credit for it. There is no penalty for not doing it, but if you will receive marks for getting it correct.
Tuesday, 25 October 2011
Project Link
https://docs.google.com/spreadsheet/viewform?hl=en_US&formkey=dGg5QTE3d3A4OHpmMFFHLTVnTFNsZ0E6MQ#gid=0
Monday, 24 October 2011
Oblique Triangle Trigonometry
-How to use sine law to determine side lengths and angle measures in obtuse triangles.
-How to use the cosine law to determine side lengths and angle measures in obtuse triangles.
-Solving problems that can be modelled using obtuse triangles.
In class we worked on a problem together. The problem is as follows:
On a dogleg hole, golfers have a choice between playing it safe and making the green in two shots or taking a chance and trying for the green in one shot. Jay can hit a ball between 170 and 190 yards from the tree with a 3-iron. Is it possible for Jay to make it to the green at this hole in one shot with a 3-iron? Explain.
This is the diagram we drew:
We figured out what side “a” was by using cosine law.
a(squared)= 51(squared) + 160(squared) - 2(51)(160) cos110
a=184 yrds.
Therefore, yes he could make it to the green in one shot.
After that, we filled in the chart on page 162 and compared our answers with a partner.
Next is Allysa! (:
By Kelsey.
Saturday, 22 October 2011
Solving Problems Using Acute Triangles
next will be Allysa
Monday, 17 October 2011
Proving and Applying the Sine Law
We we went through the examples on pages 118-123 to get more of a clearifiactaion as to how to use the formulas.
We finished class off with an assignment on page 125.
Next will be Tanner! :)
Tuesday, 11 October 2011
Chapter 3
today we needed a calculator.
We found that you must add a line segment to use trig ratios. We split the 6 ft line in half and joined it with the vertex across from it. We now formed two 90 degree angles. We then used sine to find the length of the unknown side. We continued by using trig and found that the goal was 5.43 feet. ... We were wrong. The answer is still unknown.
We then did our chapter 3 diagnostic test.
Next will be the girl who sits beside me.
:)
Thursday, 6 October 2011
2.4 angle properties in polygons
- you can prove properties of angles in polgons using other angle properties that have already been proved
need to know
- the sum of the measures of the interior angles of a convex polygon with N sides can be expressed as 180 degrees(n-2)
- the measure of each interior angle of a regular polygon is 180 (n-2)
_____
n
- the sum of the measures of the exterior angles of any convex polygon is 360 degrees
ex: if a polygon has 15 sides what is the sum of the interior angles
answer: 15-2=13
13x180=2340
2340/15=156
answer is 156
next is sarah donald!!!
Monday, 3 October 2011
Angle Properties in Polygons
next is stelzer
Drawing and painting online tool
Math 20 Foundations Exam
This week will be a busy week in Math Foundations 20.
On Wednesday, Oct. 5 we will write a Practice Exam for Chapter 2.
On Thursday we will be in the Writing Lab. We will work on our Logo Design Assignment (Chapter Task 2) and also select a topic for our Course Project. The Logo Design task is due on Tuesday after the long weekend, October 11.
On Friday, October 7 we will be writing the Chapter 2 Exam.
Have a great week. If you need any extra help, come and see me!
Long-Awaited Thursday Post (Now With More Friday!)
On Friday we talked about non-adjacent interior angles (Sounds fun)! Non- adjacent Interior Angles are two angles of a triangle that do not have the same vertex as an exterior angle. In the picture, angle X and angle Y are non-adjacent interior angles to angle Z! We discovered that the measure of an exterior angle of a triangle is equal to the sum of the measures of the two non- adjacent interior angles (which is pretty cool because it shows the neat relations between the sides of a triangle!). We had an assignment to do and it was page 90, #1-3, 5, 6, 8, 9, and 12! Big assignment, but I'm sure we all got it done, RIIIIIGHT??
Friday, 30 September 2011
Mid-Chapter Review
The next to post in the blog will be Tanner.
Monday, 26 September 2011
Angles Formed by Parallel Lines
We started off class by looking over our Chapter 2 diagnostic work sheet and correcting a classmates to show Mr.Banow our knowledge in this unit so far.
Converse is a statement that is formed by switching the premise and the conclusion of another statement.
Next we worked on page 72 which is reviewing parallel lines and transversals.
We reviewed what Alternate Interior and Exterior angles were.
Alternate interior angles are two non-adjacent interior angles on opposite sides of a transversal. Which is angles 3,6 and 4,5.
Alternate exterior angles are two exterior angles formed between two lines and a transversal, on opposite sides of the transversal. Which is angles 1,8 and 2,7.
We also reviewed what Supplementary and Complementary angles were. Two angles are Supplementary angles if they add up to 180 degrees. These two angles (140 degrees and 40 degrees) are Supplementary Angles, because they add up to 180 degrees. These two angles (40 degrees and 50 degrees) are Complementary Angles, because they add up to 90 degrees.
The next person to blog will be, AARON. :)
OH YAH, and don't forget to bring a compass, protractor and ruler ASAP.
Exploring Parallel Lines
Our class did a hand out assignment on this and then we went over all the answers as a class and i believe it went very well because our class is very smart.
Next will be michelle :)
Friday, 23 September 2011
properties of angles and triangles. :)
we worked on a sheet to test our knowledge about triangles and angles and then worked on a dog activity on page 68. Most groups failed at the objective of making a dog using polygons.
this is all.
peeace.
next is............. cody. :)
Sunday, 18 September 2011
Analyzing Puzzles and Games
In summary: Both inductive and deductive reasoning can be useful for determining a strategy to solve a puzzle or win a game. Inductive reasoning is useful when analyzing games and puzzles that require recognizing patterns or creating a particular order. Deductive reasoning is useful when analyzing games and puzzles that require inquiry and discovery to complete.
we ended class with an assignment on page 55. #5,6,7,9,11
Next post will be from Amy! yay!
Thursday, 15 September 2011
1.6 Recap & 1.7: Analyzing Puzzles and Games
Wednesday, 14 September 2011
Reasoning To Solve Problems
To improve problem solving it would help to understand inductive and deductive reasoning. Deductive reasoning is based on facts that lead to a logical explanation, where as inductive reasoning is based on simple patterns to try and solve the problem.
Example of a deductive problem:
Mammals have hair. Dogs are mammals. So therefore, dogs have hair.
Conclusion:
Based on the statement, the answer is deductive because it demonstrates proof in the original statement.
Mammals have hair. (Which is all mammals, not just dogs)
Dogs are mammals. (Mammals have hair)
So we can come to the conclusion that, yes, all dogs have hair because there are mammals. There is proof stated, so the answer cannot be inductive, the statement is deductive.
- Next is Alex :)
Tuesday, 13 September 2011
SEPT 13
summary:
a single error in reasoningwill break down the logical argument of a deductive proof. this will result in an invalid conclusion, of a conclusion that is not supported buy the proof.
trying to divide by 0 will always cause a proof to be wrong, leading to an conclusion that is also wrong. also try avoid circular reasoning. when you write a proof try to keep is that it don't take a rocket scientist to make sense of it.
an example of to days work:
identify the error: all squares have 4 right angels. Quadrilateral PQRS has 4 right angels. therefore, PQRS is a square.
answer: not true quadrilateral PQRS could be a rectangle
Next is Joel
Tuesday, 30 August 2011
Welcome to this class!
We will mainly use this blog to summarize each of our lessons. At the end of each unit it will serve as a great summary and review of what we have covered.
I encourage you to take this seriously as a useful tool to improve achievement. If you do, I think you will find that this is a great resource.